Optimal. Leaf size=99 \[ \frac {\sqrt {\frac {\pi }{2}} a^2 C\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{b^3}-\frac {\sqrt {\frac {\pi }{2}} S\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{2 b^3}-\frac {a \sin \left ((a+b x)^2\right )}{b^3}+\frac {(a+b x) \sin \left ((a+b x)^2\right )}{2 b^3} \]
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Rubi [A] time = 0.07, antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3434, 3352, 3380, 2637, 3386, 3351} \[ \frac {\sqrt {\frac {\pi }{2}} a^2 \text {FresnelC}\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{b^3}-\frac {\sqrt {\frac {\pi }{2}} S\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{2 b^3}-\frac {a \sin \left ((a+b x)^2\right )}{b^3}+\frac {(a+b x) \sin \left ((a+b x)^2\right )}{2 b^3} \]
Antiderivative was successfully verified.
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Rule 2637
Rule 3351
Rule 3352
Rule 3380
Rule 3386
Rule 3434
Rubi steps
\begin {align*} \int x^2 \cos \left ((a+b x)^2\right ) \, dx &=\frac {\operatorname {Subst}\left (\int \left (a^2 \cos \left (x^2\right )-2 a x \cos \left (x^2\right )+x^2 \cos \left (x^2\right )\right ) \, dx,x,a+b x\right )}{b^3}\\ &=\frac {\operatorname {Subst}\left (\int x^2 \cos \left (x^2\right ) \, dx,x,a+b x\right )}{b^3}-\frac {(2 a) \operatorname {Subst}\left (\int x \cos \left (x^2\right ) \, dx,x,a+b x\right )}{b^3}+\frac {a^2 \operatorname {Subst}\left (\int \cos \left (x^2\right ) \, dx,x,a+b x\right )}{b^3}\\ &=\frac {a^2 \sqrt {\frac {\pi }{2}} C\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{b^3}+\frac {(a+b x) \sin \left ((a+b x)^2\right )}{2 b^3}-\frac {\operatorname {Subst}\left (\int \sin \left (x^2\right ) \, dx,x,a+b x\right )}{2 b^3}-\frac {a \operatorname {Subst}\left (\int \cos (x) \, dx,x,(a+b x)^2\right )}{b^3}\\ &=\frac {a^2 \sqrt {\frac {\pi }{2}} C\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{b^3}-\frac {\sqrt {\frac {\pi }{2}} S\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )}{2 b^3}-\frac {a \sin \left ((a+b x)^2\right )}{b^3}+\frac {(a+b x) \sin \left ((a+b x)^2\right )}{2 b^3}\\ \end {align*}
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Mathematica [A] time = 0.28, size = 76, normalized size = 0.77 \[ -\frac {-2 \sqrt {2 \pi } a^2 C\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )+\sqrt {2 \pi } S\left (\sqrt {\frac {2}{\pi }} (a+b x)\right )+2 (a-b x) \sin \left ((a+b x)^2\right )}{4 b^3} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.82, size = 112, normalized size = 1.13 \[ \frac {2 \, \sqrt {2} \pi a^{2} \sqrt {\frac {b^{2}}{\pi }} \operatorname {C}\left (\frac {\sqrt {2} {\left (b x + a\right )} \sqrt {\frac {b^{2}}{\pi }}}{b}\right ) - \sqrt {2} \pi \sqrt {\frac {b^{2}}{\pi }} \operatorname {S}\left (\frac {\sqrt {2} {\left (b x + a\right )} \sqrt {\frac {b^{2}}{\pi }}}{b}\right ) + 2 \, {\left (b^{2} x - a b\right )} \sin \left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}{4 \, b^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [C] time = 0.46, size = 159, normalized size = 1.61 \[ -\frac {\frac {\left (i + 1\right ) \, \sqrt {2} \sqrt {\pi } {\left (2 \, a^{2} + i\right )} \operatorname {erf}\left (\left (\frac {1}{2} i - \frac {1}{2}\right ) \, \sqrt {2} {\left (x + \frac {a}{b}\right )} {\left | b \right |}\right )}{{\left | b \right |}} + \frac {4 \, {\left (i \, b {\left (x + \frac {a}{b}\right )} - 2 i \, a\right )} e^{\left (i \, b^{2} x^{2} + 2 i \, a b x + i \, a^{2}\right )}}{b}}{16 \, b^{2}} - \frac {-\frac {\left (i - 1\right ) \, \sqrt {2} \sqrt {\pi } {\left (2 \, a^{2} - i\right )} \operatorname {erf}\left (-\left (\frac {1}{2} i + \frac {1}{2}\right ) \, \sqrt {2} {\left (x + \frac {a}{b}\right )} {\left | b \right |}\right )}{{\left | b \right |}} + \frac {4 \, {\left (-i \, b {\left (x + \frac {a}{b}\right )} + 2 i \, a\right )} e^{\left (-i \, b^{2} x^{2} - 2 i \, a b x - i \, a^{2}\right )}}{b}}{16 \, b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.03, size = 131, normalized size = 1.32 \[ \frac {x \sin \left (x^{2} b^{2}+2 a b x +a^{2}\right )}{2 b^{2}}-\frac {a \left (\frac {\sin \left (x^{2} b^{2}+2 a b x +a^{2}\right )}{2 b^{2}}-\frac {a \sqrt {2}\, \sqrt {\pi }\, \FresnelC \left (\frac {\sqrt {2}\, \left (b^{2} x +a b \right )}{\sqrt {\pi }\, \sqrt {b^{2}}}\right )}{2 b \sqrt {b^{2}}}\right )}{b}-\frac {\sqrt {2}\, \sqrt {\pi }\, \mathrm {S}\left (\frac {\sqrt {2}\, \left (b^{2} x +a b \right )}{\sqrt {\pi }\, \sqrt {b^{2}}}\right )}{4 b^{2} \sqrt {b^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [C] time = 3.19, size = 256, normalized size = 2.59 \[ \frac {a b x {\left (8 i \, e^{\left (i \, b^{2} x^{2} + 2 i \, a b x + i \, a^{2}\right )} - 8 i \, e^{\left (-i \, b^{2} x^{2} - 2 i \, a b x - i \, a^{2}\right )}\right )} + a^{2} {\left (8 i \, e^{\left (i \, b^{2} x^{2} + 2 i \, a b x + i \, a^{2}\right )} - 8 i \, e^{\left (-i \, b^{2} x^{2} - 2 i \, a b x - i \, a^{2}\right )}\right )} + 2 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2}} {\left ({\left (-\left (i - 1\right ) \, \sqrt {2} \sqrt {\pi } {\left (\operatorname {erf}\left (\sqrt {i \, b^{2} x^{2} + 2 i \, a b x + i \, a^{2}}\right ) - 1\right )} + \left (i + 1\right ) \, \sqrt {2} \sqrt {\pi } {\left (\operatorname {erf}\left (\sqrt {-i \, b^{2} x^{2} - 2 i \, a b x - i \, a^{2}}\right ) - 1\right )}\right )} a^{2} + \left (i + 1\right ) \, \sqrt {2} \Gamma \left (\frac {3}{2}, i \, b^{2} x^{2} + 2 i \, a b x + i \, a^{2}\right ) - \left (i - 1\right ) \, \sqrt {2} \Gamma \left (\frac {3}{2}, -i \, b^{2} x^{2} - 2 i \, a b x - i \, a^{2}\right )\right )}}{16 \, {\left (b^{4} x + a b^{3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.15, size = 80, normalized size = 0.81 \[ \frac {x\,\sin \left ({\left (a+b\,x\right )}^2\right )}{2\,b^2}-\frac {a\,\sin \left ({\left (a+b\,x\right )}^2\right )}{2\,b^3}-\frac {\sqrt {2}\,\sqrt {\pi }\,\mathrm {S}\left (\frac {\sqrt {2}\,\left (a+b\,x\right )}{\sqrt {\pi }}\right )}{4\,b^3}+\frac {\sqrt {2}\,a^2\,\sqrt {\pi }\,\mathrm {C}\left (\frac {\sqrt {2}\,\left (a+b\,x\right )}{\sqrt {\pi }}\right )}{2\,b^3} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{2} \cos {\left (a^{2} + 2 a b x + b^{2} x^{2} \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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